Lab
By: rooneynguyen555 • October 15, 2013 • Essay • 620 Words (3 Pages) • 1,460 Views
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HETP of column packing:
Reflux Ratio:
Figure 1; Standard Scale
Vials Temperture (Celsius) Mass of Empty Vial with Cap (g) Mass after Distillation (g) Mass of Distilled Solution (g)
HETP 81 9.009 9.116 0.107
Vial 1 81-84 18.851 20.562 1.711
Vial 2 85-96 17.554 28.320 10.766
Vial 3 97-106 17.556 22.149 4.593
Vial 4 107-111 16.980 22.765 5.785
Micro-scale
Height of Column Packing: __ mL
Mass of Cyclohexane from gas chromatography:
Mass of Toluene from gas chromatography:
Moles of Cyclohexane: 1.29 mol cyclohexane
Moles of Toluene: 0.0265 mol toluene
Total number of theoretical plates: 3.23
Number of plates by column: 2.23
HETP of column packing:
Reflux Ratio:
Figure 2; Micro Scale
Vials Temperture (Celsius) Mass of Empty Vials with Cap (g) Mass after Distillation (g) Mass of Distilled Solution (g)
HETP 81 8.803g 8.810 0.007
Vial 1 81-84 16.798 16.850 0.052
Vial 2 85-96 17.404 17.505 0.101
Vial 3 97-106 16.940 16.952 0.012
Vial 4 107-111 17.149g 17.156 0.007
Calculations
Standard Scale
HETP
A: (92.63384)(1.11) = (102.823562 g) / (84.16 g/mol cyclohexane) = nA = 1.22 mol cyclohexane
B: (7.36611)(1.05) = (7.7344155 g)/ (92.14 g/mol toluene) = nB = 0.0839 mol toluene
Total # theoretical plates = (log nA/log nB) / log ? = log (1.22/0.0839) / log(2.33) = 3.16
3.16-1 = 2.16 provided by the column.
Sample #1
A: (88.03853)(1.11) = (97.7227683 g) / (84.16 g/mol cyclohexane) = nA = 1.16 mol cyclohexane
B: (11.65914)(1.05) = (12.242097 g) / (92.14 g/mol toluene) = nB = 0.133 mol toulene
Molar % A: (100%)(nA / nA + nB) = (100%)(1.16 / 1.16 + 0.133) = 89.71%
Molar % B: (100%)(nB / nB + nA) = (100%)(0.133 / 0.133 + 1.16) = 10.29%
Avg. Temp: 81? +84? = 165/2 = 82.5?
Sample #2
A: (74.42797)(1.11) = (82.615046 g) / (84.16 g/mol cyclohexane) = nA = 0.982 mol cyclohexane
B: (25.57202)(1.05) = (26.850621 g) / (92.14 g/mol toluene) = nB = 0.291 mol toulene
Molar % A: (100%)(nA / nA + nB) = (100%)(0.982 / 0.982 + 0.291 ) = 77.14 %
Molar % B: (100%)(nB / nB + nA) = (100%)(0.291 / 0.291 + 0.982 ) = 22.86%
Avg. Temp: 85? + 96? = 181/2 = 90.5?
Sample #3
A: (40.16184)(1.11) = (44.5796424 g) / (84.16 g/mol cyclohexane) = nA = 0.53 mol cyclohexane
B: (59.83816)(1.05) = (62.830068 g) / (92.14 g/mol toluene) = nB = 0.68 mol toulene
Molar
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