Fin 441 Homework1
By: dantong • February 15, 2017 • Exam • 889 Words (4 Pages) • 3,081 Views
Page 1 of 4
Homework 1 (Call/Put options)
- Consider an option that expires in 72 days. The bid and ask discounts on the T-bill are $7.44 and $7.20 respectively, Find the appropriate risk free rate. (Assuming1 year, $100 T-bill).
- Bid (purchase) = ($100 - $7.44) = $92.56
- Ask (sell) = ($100 - $7.20) = $92.80
- Average discount = ($7.44 +$7.2)/2 = $7.32
- 72 day T-bill = $100 – ($7.32)(72/360) = $98.536
- Risk free rate = ($100/$98.536)^(365/72) – 1 = 7.76%
For questions 2-6 current stock price is 165.13. The expirations are July 17, August 21, and October 16. Risk free rates are .0516, .0550, and .0588 respectively.
- Compute the intrinsic values, time values, and lower bounds of the following calls.
- July 160
- Intrinsic value = $165.13 - $160 = $5.13
- Time Value = $6 - $5.13 = $0.87
- Lower bound ≥ Max(0, $165.13 - $160(1+.0516)^(-.038356)) = $5.44
- October 155
- Intrinsic value = $165.13 - $155 = $10.13
- Time Value = $14 - $10.13 = $3.87
- Lower bound ≥ Max(0, $165.13 - $155(1+.0588)^(-.282192)) = $12.61
- August 170
- Intrinsic value = $165.13 - $170 = -$4.87
- Time Value = $3.20 - $4.87 = -$1.67
- Lower bound ≥ Max(0, $165.13 - $170(1+.0550)^(-.131507)) = $0.00
- Compute the intrinsic values, time values, and lower bounds of the following puts.
- July 165
- Intrinsic value = $165 - $165.13 = -$0.13
- Time Value = $2.35 - $0.13 = -$2.22
- Lower bound ≥ Max(0, $165(1+.0516)^(-.038356) - $165.13) = $0.00
- August 160
- Intrinsic value = $160 - $165.13 = -$5.13
- Time Value = $2.75 - $5.13 = -$2.38
- Lower bound ≥ Max(0, $160(1+.0550)^(-.131507) – $165.13) = $0.00
- October 170
- Intrinsic value = $170 - $165.13 = $4.87
- Time Value = $9 - $4.87 = $4.13
- Lower bound ≥ Max(0, $170(1+.0588)^(-.282192) - $165.13) = $2.15
- Check the following combinations of puts and calls, determine whether they conform to the put-call parity, for European options, and identify violations if any.
- July 155
- Pe($165.13 + $0.20) = Ce($10.50 + $155(1+.0516)^(-.038356))
$165.33 = $165.20
- Difference ≥ $0.10, put-call parity has been violated
- August 160
- Pe($165.13 + $2.75) = Ce($8.10 + $160(1+.0550)^(-.131507))
$167.88 = $166.98
- Difference ≥ $0.10, put-call parity has been violated
- October 170
- Pe($165.13 + $9.00) = Ce($6.00 + $170(1+.0588)^(-.282192))
$174.13 = $173.28
- Difference ≥ $0.10, put-call parity has been violated
- Examine the following pairs of American calls which differ only by exercise price. Determine whether the rules regarding relationship between American calls that differ only by exercise price are violated.
- August 155 and 160
- Max difference = $160 - $155 = $5
- Actual difference = $11.80 - $8.10 = $3.70
- Actual difference ≤ Max difference, rules not violated
- October 160 and 165
- Max difference = $165 - $160 = $5
- Actual difference = $11.10 - $8.10 = $3.00
- Actual difference ≤ Max difference, rules not violated
- Examine the following pairs of American puts which differ only by exercise price. Determine whether the rules regarding relationship between American puts that differ only by exercise price are violated.
- August 155 and 160
- Max difference = $160 - $155 = $5
- Actual difference = $2.75 - $1.25 = $1.50
- Actual difference ≤ Max difference, rules not violated
- October 160 and 170
- Max difference = $170 - $160 = $10
- Actual difference = $9.00 - $4.50 = $3.70
- Actual difference ≤ Max difference, rules not violated
...